What are the solutions to the equation 0=x^2-4x-6 ?

The solutions to the equation 0=x^2-4x-6 are x=2+sqrt(10),x=2-sqrt(10)

Find the zeros of 0=x^2-4x-6

The zeros of 0=x^2-4x-6 are x=2+sqrt(10),x=2-sqrt(10)

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0 = x^{2} - 4 x - 6

x = 2 + 10, x = 2 - 10

Solution steps

0 = x^{2} - 4 x - 6

Switch sides

x^{2} - 4 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 6 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 6) = 210

x_{1, 2} = \frac{- ( - 4 ) \pm 2 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 10}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 2 10}{2 \cdot 1}

x = \frac{- ( - 4 ) + 2 10}{2 \cdot 1} : 2 + 10

x = \frac{- ( - 4 ) - 2 10}{2 \cdot 1} : 2 - 10

The solutions to the quadratic equation are:

x = 2 + 10, x = 2 - 10

(x - 4)^{2} \leq 0

\frac{x - 7}{4} + \frac{2 x}{3} = - \frac{43}{12}

1 5^{5}

∣ x - 1 ∣ > 9

\frac{\frac{π ( 50 ) ^{2}}{4} 200}{600} (- 0.162)

What are the solutions to the equation 0=x^2-4x-6 ?
The solutions to the equation 0=x^2-4x-6 are x=2+sqrt(10),x=2-sqrt(10)
Find the zeros of 0=x^2-4x-6
The zeros of 0=x^2-4x-6 are x=2+sqrt(10),x=2-sqrt(10)