What are the solutions to the equation 3s^2+10s+6=30 ?

The solutions to the equation 3s^2+10s+6=30 are s=(-5+sqrt(97))/3 ,s=-(5+sqrt(97))/3

Find the zeros of 3s^2+10s+6=30

The zeros of 3s^2+10s+6=30 are s=(-5+sqrt(97))/3 ,s=-(5+sqrt(97))/3

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3 s^{2} + 10 s + 6 = 30

s = \frac{- 5 + 97}{3}, s = - \frac{5 + 97}{3}

Solution steps

3 s^{2} + 10 s + 6 = 30

Move

30

to the left side

3 s^{2} + 10 s - 24 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 3 ( - 24 )}{2 \cdot 3}

1 0^{2} - 4 \cdot 3 (- 24) = 297

s_{1, 2} = \frac{- 10 \pm 2 97}{2 \cdot 3}

Separate the solutions

s_{1} = \frac{- 10 + 2 97}{2 \cdot 3}, s_{2} = \frac{- 10 - 2 97}{2 \cdot 3}

s = \frac{- 10 + 2 97}{2 \cdot 3} : \frac{- 5 + 97}{3}

s = \frac{- 10 - 2 97}{2 \cdot 3} : - \frac{5 + 97}{3}

The solutions to the quadratic equation are:

s = \frac{- 5 + 97}{3}, s = - \frac{5 + 97}{3}

3 a^{2} - 12 a

5 u^{2} v^{2} - 20 v^{2} + 15 u^{2} - 60

\frac{e ^{- 5 \cdot 1.5} \cdot ( 5 \cdot 1.5 ) ^{5}}{5 !}

- 2 x = 2

x^{3} y + x^{2} y^{2} + x^{2} yz

What are the solutions to the equation 3s^2+10s+6=30 ?
The solutions to the equation 3s^2+10s+6=30 are s=(-5+sqrt(97))/3 ,s=-(5+sqrt(97))/3
Find the zeros of 3s^2+10s+6=30
The zeros of 3s^2+10s+6=30 are s=(-5+sqrt(97))/3 ,s=-(5+sqrt(97))/3