What are the solutions to the equation x^2+8x+16=3 ?

The solutions to the equation x^2+8x+16=3 are x=-4+sqrt(3),x=-4-sqrt(3)

Find the zeros of x^2+8x+16=3

The zeros of x^2+8x+16=3 are x=-4+sqrt(3),x=-4-sqrt(3)

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x^{2} + 8 x + 16 = 3

x = - 4 + 3, x = - 4 - 3

Decimal Notation

x = - 2.26794 \dots, x = - 5.73205 \dots

Solution steps

x^{2} + 8 x + 16 = 3

Move

3

to the left side

x^{2} + 8 x + 13 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 13}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot 13 = 23

x_{1, 2} = \frac{- 8 \pm 2 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 2 3}{2 \cdot 1}, x_{2} = \frac{- 8 - 2 3}{2 \cdot 1}

x = \frac{- 8 + 2 3}{2 \cdot 1} : - 4 + 3

x = \frac{- 8 - 2 3}{2 \cdot 1} : - 4 - 3

The solutions to the quadratic equation are:

x = - 4 + 3, x = - 4 - 3

x - 20 > 24

18 x^{2} - 57 x + 35

8 x^{3} - 6 x^{2} + 12 x - 9

(\frac{n ( n + 1 )}{2})^{2} + (n + 1)^{3}

x^{3} + 3 x^{2} < 0

What are the solutions to the equation x^2+8x+16=3 ?
The solutions to the equation x^2+8x+16=3 are x=-4+sqrt(3),x=-4-sqrt(3)
Find the zeros of x^2+8x+16=3
The zeros of x^2+8x+16=3 are x=-4+sqrt(3),x=-4-sqrt(3)