What are the solutions to the equation 5x^2-20x+10=5(3x+2) ?

The solutions to the equation 5x^2-20x+10=5(3x+2) are x=7,x=0

Find the zeros of 5x^2-20x+10=5(3x+2)

The zeros of 5x^2-20x+10=5(3x+2) are x=7,x=0

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5 x^{2} - 20 x + 10 = 5 (3 x + 2)

x = 7, x = 0

Solution steps

5 x^{2} - 20 x + 10 = 5 (3 x + 2)

Expand

5 (3 x + 2) : 15 x + 10

5 x^{2} - 20 x + 10 = 15 x + 10

Move

10

to the left side

5 x^{2} - 20 x = 15 x

Move

15 x

to the left side

5 x^{2} - 35 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 35 ) \pm ( - 35 ) ^{2} - 4 \cdot 5 \cdot 0}{2 \cdot 5}

(- 35)^{2} - 4 \cdot 5 \cdot 0 = 35

x_{1, 2} = \frac{- ( - 35 ) \pm 35}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 35 ) + 35}{2 \cdot 5}, x_{2} = \frac{- ( - 35 ) - 35}{2 \cdot 5}

x = \frac{- ( - 35 ) + 35}{2 \cdot 5} : 7

x = \frac{- ( - 35 ) - 35}{2 \cdot 5} : 0

The solutions to the quadratic equation are:

x = 7, x = 0

\frac{3}{5} m - \frac{3}{4} m - \frac{2}{3} m = - \frac{4}{5}

h^{2} - 4

5 - x \leq 10

\frac{2 ^{8}}{2 ^{4}}

20 = - 16 t^{2} + 170 t + 70

What are the solutions to the equation 5x^2-20x+10=5(3x+2) ?
The solutions to the equation 5x^2-20x+10=5(3x+2) are x=7,x=0
Find the zeros of 5x^2-20x+10=5(3x+2)
The zeros of 5x^2-20x+10=5(3x+2) are x=7,x=0