What are the solutions to the equation 3x^2+15x+21=0 ?

The solutions to the equation 3x^2+15x+21=0 are x=-5/2+i(sqrt(3))/2 ,x=-5/2-i(sqrt(3))/2

Find the zeros of 3x^2+15x+21=0

The zeros of 3x^2+15x+21=0 are x=-5/2+i(sqrt(3))/2 ,x=-5/2-i(sqrt(3))/2

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3 x^{2} + 15 x + 21 = 0

x = - \frac{5}{2} + i \frac{3}{2}, x = - \frac{5}{2} - i \frac{3}{2}

Solution steps

3 x^{2} + 15 x + 21 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 15 \pm 1 5 ^{2} - 4 \cdot 3 \cdot 21}{2 \cdot 3}

Simplify

1 5^{2} - 4 \cdot 3 \cdot 21 : 33 i

x_{1, 2} = \frac{- 15 \pm 3 3 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 15 + 3 3 i}{2 \cdot 3}, x_{2} = \frac{- 15 - 3 3 i}{2 \cdot 3}

x = \frac{- 15 + 3 3 i}{2 \cdot 3} : - \frac{5}{2} + i \frac{3}{2}

x = \frac{- 15 - 3 3 i}{2 \cdot 3} : - \frac{5}{2} - i \frac{3}{2}

The solutions to the quadratic equation are:

x = - \frac{5}{2} + i \frac{3}{2}, x = - \frac{5}{2} - i \frac{3}{2}

\frac{n}{5} > \frac{7}{4}

- 3 < x \leq 6

\frac{- 2}{6}

- (4 x - 6) + 9 = 7 x - (1 - 6 x)

7 c^{2} - 2 c - 9

What are the solutions to the equation 3x^2+15x+21=0 ?
The solutions to the equation 3x^2+15x+21=0 are x=-5/2+i(sqrt(3))/2 ,x=-5/2-i(sqrt(3))/2
Find the zeros of 3x^2+15x+21=0
The zeros of 3x^2+15x+21=0 are x=-5/2+i(sqrt(3))/2 ,x=-5/2-i(sqrt(3))/2