What is 3/(\frac{8){1/(-7)}} ?

The solution to 3/(\frac{8){1/(-7)}} is -3/56

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simplify 3/(\frac{8){1/(-7)}}

simplify

\frac{3}{\frac{8}{\frac{1}{- 7}}}

- \frac{3}{56}

Decimal Notation

- 0.05357 \dots

Solution steps

\frac{3}{\frac{8}{\frac{1}{- 7}}}

Apply the fraction rule:

\frac{a}{\frac{b}{c}} = \frac{a \cdot c}{b}

= \frac{3 \cdot \frac{1}{- 7}}{8}

Apply the fraction rule:

\frac{a}{- b} = - \frac{a}{b}

\frac{1}{- 7} = - \frac{1}{7}

= \frac{3 ( - \frac{1}{7} )}{8}

Apply rule:

a (- b) = - ab

3 (- \frac{1}{7}) = - 3 \cdot \frac{1}{7}

= \frac{- 3 \cdot \frac{1}{7}}{8}

- 3 \cdot \frac{1}{7} = - \frac{3}{7}

= \frac{- \frac{3}{7}}{8}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{\frac{3}{7}}{8}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

\frac{\frac{3}{7}}{8} = \frac{3}{7 \cdot 8}

= - \frac{3}{7 \cdot 8}

Multiply the numbers:

7 \cdot 8 = 56

= - \frac{3}{56}

4 (k + 2) - 3 k \leq 12

2 \cdot 5^{3}

b^{2} + 3 b - 4

3 x^{2} + 12 x - 39 = 0

\frac{3 ( 2 t + 2 )}{2} > \frac{t - 3}{4} + \frac{t}{3}