What are the solutions to the equation p^2-19p+84=0 ?

The solutions to the equation p^2-19p+84=0 are p=12,p=7

Find the zeros of p^2-19p+84=0

The zeros of p^2-19p+84=0 are p=12,p=7

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p^{2} - 19 p + 84 = 0

p = 12, p = 7

Solution steps

p^{2} - 19 p + 84 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 19 ) \pm ( - 19 ) ^{2} - 4 \cdot 1 \cdot 84}{2 \cdot 1}

(- 19)^{2} - 4 \cdot 1 \cdot 84 = 5

p_{1, 2} = \frac{- ( - 19 ) \pm 5}{2 \cdot 1}

Separate the solutions

p_{1} = \frac{- ( - 19 ) + 5}{2 \cdot 1}, p_{2} = \frac{- ( - 19 ) - 5}{2 \cdot 1}

p = \frac{- ( - 19 ) + 5}{2 \cdot 1} : 12

p = \frac{- ( - 19 ) - 5}{2 \cdot 1} : 7

The solutions to the quadratic equation are:

p = 12, p = 7

6 x + 2 + 6 x < 14

\frac{208}{143}

lo g_{3} (9) = y

2 x + 3 < 4 x - 1

\frac{2}{3} + \frac{1}{9} + \frac{3}{5}

What are the solutions to the equation p^2-19p+84=0 ?
The solutions to the equation p^2-19p+84=0 are p=12,p=7
Find the zeros of p^2-19p+84=0
The zeros of p^2-19p+84=0 are p=12,p=7