What are the solutions to the equation 72=2pir^2 ?

The solutions to the equation 72=2pir^2 are r= 6/(sqrt(pi)),r=-6/(sqrt(pi))

Find the zeros of 72=2pir^2

The zeros of 72=2pir^2 are r= 6/(sqrt(pi)),r=-6/(sqrt(pi))

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72 = 2 π r^{2}

r = \frac{6}{π}, r = - \frac{6}{π}

Solution steps

72 = 2 π r^{2}

Switch sides

2 π r^{2} = 72

Divide both sides by

2 π

r^{2} = \frac{36}{π}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

r = \frac{36}{π}, r = - \frac{36}{π}

\frac{36}{π} = \frac{6}{π}

- \frac{36}{π} = - \frac{6}{π}

r = \frac{6}{π}, r = - \frac{6}{π}

\frac{7 3}{3} \cdot 2

5 x^{2} - 56 x + 11

2 y^{2} + 5 y + 3

0 = - 26.47 x^{2} + 62.557 x + 332.16

5 x^{2} + 7 x < 6

What are the solutions to the equation 72=2pir^2 ?
The solutions to the equation 72=2pir^2 are r= 6/(sqrt(pi)),r=-6/(sqrt(pi))
Find the zeros of 72=2pir^2
The zeros of 72=2pir^2 are r= 6/(sqrt(pi)),r=-6/(sqrt(pi))