What are the solutions to the equation 4x^2+4x+5=0 ?

The solutions to the equation 4x^2+4x+5=0 are x=-1/2+i,x=-1/2-i

Find the zeros of 4x^2+4x+5=0

The zeros of 4x^2+4x+5=0 are x=-1/2+i,x=-1/2-i

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4 x^{2} + 4 x + 5 = 0

x = - \frac{1}{2} + i, x = - \frac{1}{2} - i

Solution steps

4 x^{2} + 4 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 4 \cdot 5}{2 \cdot 4}

Simplify

4^{2} - 4 \cdot 4 \cdot 5 : 8 i

x_{1, 2} = \frac{- 4 \pm 8 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 4 + 8 i}{2 \cdot 4}, x_{2} = \frac{- 4 - 8 i}{2 \cdot 4}

x = \frac{- 4 + 8 i}{2 \cdot 4} : - \frac{1}{2} + i

x = \frac{- 4 - 8 i}{2 \cdot 4} : - \frac{1}{2} - i

The solutions to the quadratic equation are:

x = - \frac{1}{2} + i, x = - \frac{1}{2} - i

\frac{b}{75} = \frac{2}{15}

5 x^{2} + 60 x + 180 = 0

3 x^{2} - 2 x y + 6 x - 4 y

c = 400 e^{- 3 (0.23)}

x^{2} - 16 = 15 x

What are the solutions to the equation 4x^2+4x+5=0 ?
The solutions to the equation 4x^2+4x+5=0 are x=-1/2+i,x=-1/2-i
Find the zeros of 4x^2+4x+5=0
The zeros of 4x^2+4x+5=0 are x=-1/2+i,x=-1/2-i