What are the solutions to the equation t^2+3t=0 ?

The solutions to the equation t^2+3t=0 are t=0,t=-3

Find the zeros of t^2+3t=0

The zeros of t^2+3t=0 are t=0,t=-3

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t^{2} + 3 t = 0

t = 0, t = - 3

Solution steps

t^{2} + 3 t = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot 0 = 3

t_{1, 2} = \frac{- 3 \pm 3}{2 \cdot 1}

Separate the solutions

t_{1} = \frac{- 3 + 3}{2 \cdot 1}, t_{2} = \frac{- 3 - 3}{2 \cdot 1}

t = \frac{- 3 + 3}{2 \cdot 1} : 0

t = \frac{- 3 - 3}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

t = 0, t = - 3

3 - 9 x = 30

\frac{4 x - 3}{5} - \frac{4 x}{3} < \frac{2 ( x - 13 )}{15}

2 (a + 4) = 20

7 - 7 x \geq 5 x - 9

What are the solutions to the equation t^2+3t=0 ?
The solutions to the equation t^2+3t=0 are t=0,t=-3
Find the zeros of t^2+3t=0
The zeros of t^2+3t=0 are t=0,t=-3