What are the solutions to the equation 3x^2=39 ?

The solutions to the equation 3x^2=39 are x=sqrt(13),x=-sqrt(13)

Find the zeros of 3x^2=39

The zeros of 3x^2=39 are x=sqrt(13),x=-sqrt(13)

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3 x^{2} = 39

x = 13, x = - 13

Decimal

x = 3.60555 \dots, x = - 3.60555 \dots

Solution steps

3 x^{2} = 39

Divide both sides by

3

x^{2} = 13

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 13, x = - 13

2 x - 10 = 4 x - 8

x^{4} - 5 x^{3}

6 x + 1 \leq - 47 or \frac{6}{7} x - 5 > 1

m + 2 \geq 3

(x + 4) (x - 6) = - 21

What are the solutions to the equation 3x^2=39 ?
The solutions to the equation 3x^2=39 are x=sqrt(13),x=-sqrt(13)
Find the zeros of 3x^2=39
The zeros of 3x^2=39 are x=sqrt(13),x=-sqrt(13)