What are the solutions to the equation 5x^2+7x-2=0 ?

The solutions to the equation 5x^2+7x-2=0 are x=(-7+sqrt(89))/(10),x=(-7-sqrt(89))/(10)

Find the zeros of 5x^2+7x-2=0

The zeros of 5x^2+7x-2=0 are x=(-7+sqrt(89))/(10),x=(-7-sqrt(89))/(10)

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5 x^{2} + 7 x - 2 = 0

x = \frac{- 7 + 89}{10}, x = \frac{- 7 - 89}{10}

Decimal Notation

x = 0.24339 \dots, x = - 1.64339 \dots

Solution steps

5 x^{2} + 7 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 5 ( - 2 )}{2 \cdot 5}

7^{2} - 4 \cdot 5 (- 2) = 89

x_{1, 2} = \frac{- 7 \pm 89}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 7 + 89}{2 \cdot 5}, x_{2} = \frac{- 7 - 89}{2 \cdot 5}

x = \frac{- 7 + 89}{2 \cdot 5} : \frac{- 7 + 89}{10}

x = \frac{- 7 - 89}{2 \cdot 5} : \frac{- 7 - 89}{10}

The solutions to the quadratic equation are:

x = \frac{- 7 + 89}{10}, x = \frac{- 7 - 89}{10}

17.95 + 0.82 x = 172.11

k (k + 40) - 10 k + 20 k = 490

\frac{c ^{2} d ^{5}}{c ^{5} d}

r^{2} + 10 r + 29 = 0

\frac{3 x}{2} - 10 = \frac{1}{2}

What are the solutions to the equation 5x^2+7x-2=0 ?
The solutions to the equation 5x^2+7x-2=0 are x=(-7+sqrt(89))/(10),x=(-7-sqrt(89))/(10)
Find the zeros of 5x^2+7x-2=0
The zeros of 5x^2+7x-2=0 are x=(-7+sqrt(89))/(10),x=(-7-sqrt(89))/(10)