What are the solutions to the equation x^2-2x=5 ?

The solutions to the equation x^2-2x=5 are x=1+sqrt(6),x=1-sqrt(6)

Find the zeros of x^2-2x=5

The zeros of x^2-2x=5 are x=1+sqrt(6),x=1-sqrt(6)

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x^{2} - 2 x = 5

x = 1 + 6, x = 1 - 6

Decimal Notation

x = 3.44948 \dots, x = - 1.44948 \dots

Solution steps

x^{2} - 2 x = 5

Move

5

to the left side

x^{2} - 2 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 5 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 5) = 26

x_{1, 2} = \frac{- ( - 2 ) \pm 2 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 6}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 2 6}{2 \cdot 1}

x = \frac{- ( - 2 ) + 2 6}{2 \cdot 1} : 1 + 6

x = \frac{- ( - 2 ) - 2 6}{2 \cdot 1} : 1 - 6

The solutions to the quadratic equation are:

x = 1 + 6, x = 1 - 6

x = 0.206 \cdot 9 0^{- 0.12} + 0.28 \cdot 9 0^{- 0.6}

25 x + 20

25 x^{2} - 9

k = \frac{4 \cdot 5}{3 \cdot 3.849}

\frac{6 ^{5}}{6}

What are the solutions to the equation x^2-2x=5 ?
The solutions to the equation x^2-2x=5 are x=1+sqrt(6),x=1-sqrt(6)
Find the zeros of x^2-2x=5
The zeros of x^2-2x=5 are x=1+sqrt(6),x=1-sqrt(6)