What are the solutions to the equation 6x^2+12=0 ?

The solutions to the equation 6x^2+12=0 are x=sqrt(2)i,x=-sqrt(2)i

Find the zeros of 6x^2+12=0

The zeros of 6x^2+12=0 are x=sqrt(2)i,x=-sqrt(2)i

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6 x^{2} + 12 = 0

x = 2 i, x = - 2 i

Solution steps

6 x^{2} + 12 = 0

Move

12

to the right side

6 x^{2} = - 12

Divide both sides by

6

x^{2} = - 2

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 2, x = - - 2

- 2 = 2 i

- - 2 = - 2 i

x = 2 i, x = - 2 i

- x^{2} + 9 > 0

(x - 8)^{\frac{7}{2}} - 64 (x - 8)^{\frac{3}{2}}

3 z - 8 + 6 z - 12 = z - 10 + 9 z - 13

45 = \frac{45}{360} \cdot 2 (6)

0.36 = - 2 \cdot 1 0^{- 6} x^{2} + 0.0011 x + 0.3548

What are the solutions to the equation 6x^2+12=0 ?
The solutions to the equation 6x^2+12=0 are x=sqrt(2)i,x=-sqrt(2)i
Find the zeros of 6x^2+12=0
The zeros of 6x^2+12=0 are x=sqrt(2)i,x=-sqrt(2)i