What are the solutions to the equation 0=x^2+4x ?

The solutions to the equation 0=x^2+4x are x=0,x=-4

Find the zeros of 0=x^2+4x

The zeros of 0=x^2+4x are x=0,x=-4

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0 = x^{2} + 4 x

x = 0, x = - 4

Solution steps

0 = x^{2} + 4 x

Switch sides

x^{2} + 4 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot 0 = 4

x_{1, 2} = \frac{- 4 \pm 4}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 4}{2 \cdot 1}, x_{2} = \frac{- 4 - 4}{2 \cdot 1}

x = \frac{- 4 + 4}{2 \cdot 1} : 0

x = \frac{- 4 - 4}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

x = 0, x = - 4

4 \cdot \frac{3}{4}

b^{2} - 4 = 0

x^{2} \cdot \frac{157}{8} + \frac{51}{4} \cdot \frac{4553}{816} = 0

\frac{x}{2} - \frac{x}{5} = 2

\frac{1}{2} (x + 2) + \frac{3}{4} (x + 4) = x + 5

What are the solutions to the equation 0=x^2+4x ?
The solutions to the equation 0=x^2+4x are x=0,x=-4
Find the zeros of 0=x^2+4x
The zeros of 0=x^2+4x are x=0,x=-4