What are the solutions to the equation 2x^2+4=0 ?

The solutions to the equation 2x^2+4=0 are x=sqrt(2)i,x=-sqrt(2)i

Find the zeros of 2x^2+4=0

The zeros of 2x^2+4=0 are x=sqrt(2)i,x=-sqrt(2)i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x^{2} + 4 = 0

x = 2 i, x = - 2 i

Solution steps

2 x^{2} + 4 = 0

Move

4

to the right side

2 x^{2} = - 4

Divide both sides by

2

x^{2} = - 2

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 2, x = - - 2

- 2 = 2 i

- - 2 = - 2 i

x = 2 i, x = - 2 i

x^{2} + 11 x + 30

2 z - 12 > 6

w + \frac{4}{5} > \frac{1}{4}

5 a^{3} - 25 a^{2} + 15 a

What are the solutions to the equation 2x^2+4=0 ?
The solutions to the equation 2x^2+4=0 are x=sqrt(2)i,x=-sqrt(2)i
Find the zeros of 2x^2+4=0
The zeros of 2x^2+4=0 are x=sqrt(2)i,x=-sqrt(2)i