What are the solutions to the equation 4x^2-9x+5=0 ?

The solutions to the equation 4x^2-9x+5=0 are x= 5/4 ,x=1

Find the zeros of 4x^2-9x+5=0

The zeros of 4x^2-9x+5=0 are x= 5/4 ,x=1

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4 x^{2} - 9 x + 5 = 0

x = \frac{5}{4}, x = 1

Decimal Notation

x = 1.25, x = 1

Solution steps

4 x^{2} - 9 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 4 \cdot 5}{2 \cdot 4}

(- 9)^{2} - 4 \cdot 4 \cdot 5 = 1

x_{1, 2} = \frac{- ( - 9 ) \pm 1}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 1}{2 \cdot 4}, x_{2} = \frac{- ( - 9 ) - 1}{2 \cdot 4}

x = \frac{- ( - 9 ) + 1}{2 \cdot 4} : \frac{5}{4}

x = \frac{- ( - 9 ) - 1}{2 \cdot 4} : 1

The solutions to the quadratic equation are:

x = \frac{5}{4}, x = 1

(2 + i) (2 - i)

(\frac{5}{2})^{4}

∣ x - 4 ∣ > 3

3 m^{3} + 3 m^{2} - 18 m

\frac{y}{5} - 15 = 7

What are the solutions to the equation 4x^2-9x+5=0 ?
The solutions to the equation 4x^2-9x+5=0 are x= 5/4 ,x=1
Find the zeros of 4x^2-9x+5=0
The zeros of 4x^2-9x+5=0 are x= 5/4 ,x=1