What are the solutions to the equation y^2-2y=-9/2 ?

The solutions to the equation y^2-2y=-9/2 are y=1+isqrt(7/2),y=1-isqrt(7/2)

Find the zeros of y^2-2y=-9/2

The zeros of y^2-2y=-9/2 are y=1+isqrt(7/2),y=1-isqrt(7/2)

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y^{2} - 2 y = - \frac{9}{2}

y = 1 + i \frac{7}{2}, y = 1 - i \frac{7}{2}

Solution steps

y^{2} - 2 y = - \frac{9}{2}

Multiply both sides by

2

2 y^{2} - 4 y = - 9

Move

9

to the left side

2 y^{2} - 4 y + 9 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 2 \cdot 9}{2 \cdot 2}

Simplify

(- 4)^{2} - 4 \cdot 2 \cdot 9 : 214 i

y_{1, 2} = \frac{- ( - 4 ) \pm 2 14 i}{2 \cdot 2}

Separate the solutions

y_{1} = \frac{- ( - 4 ) + 2 14 i}{2 \cdot 2}, y_{2} = \frac{- ( - 4 ) - 2 14 i}{2 \cdot 2}

y = \frac{- ( - 4 ) + 2 14 i}{2 \cdot 2} : 1 + i \frac{7}{2}

y = \frac{- ( - 4 ) - 2 14 i}{2 \cdot 2} : 1 - i \frac{7}{2}

The solutions to the quadratic equation are:

y = 1 + i \frac{7}{2}, y = 1 - i \frac{7}{2}

2 x + 6 \geq 4 x

- 2 x + 6 < - 2

2 y = 0

\frac{6}{7} - \frac{1}{5} w \geq \frac{4}{5}

8 x^{2} - 6 x + 1 = 0

What are the solutions to the equation y^2-2y=-9/2 ?
The solutions to the equation y^2-2y=-9/2 are y=1+isqrt(7/2),y=1-isqrt(7/2)
Find the zeros of y^2-2y=-9/2
The zeros of y^2-2y=-9/2 are y=1+isqrt(7/2),y=1-isqrt(7/2)