What are the solutions to the equation 40^2+9^2=x^2 ?

The solutions to the equation 40^2+9^2=x^2 are x=41,x=-41

Find the zeros of 40^2+9^2=x^2

The zeros of 40^2+9^2=x^2 are x=41,x=-41

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4 0^{2} + 9^{2} = x^{2}

x = 41, x = - 41

Solution steps

4 0^{2} + 9^{2} = x^{2}

Switch sides

x^{2} = 4 0^{2} + 9^{2}

Simplify

4 0^{2} + 9^{2} : 1681

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 1681, x = - 1681

1681 = 41

- 1681 = - 41

x = 41, x = - 41

\frac{10 !}{2 ! ( 10 - 2 ) !}

(- 125 x^{- 6})^{\frac{1}{3}}

\frac{3}{4} x + 8 < 41

x^{2} + 24 x + 144 = 9

x^{2} = 6 x - 45

What are the solutions to the equation 40^2+9^2=x^2 ?
The solutions to the equation 40^2+9^2=x^2 are x=41,x=-41
Find the zeros of 40^2+9^2=x^2
The zeros of 40^2+9^2=x^2 are x=41,x=-41