What is the answer to (x-12)/4+x/2+(x-2x)/9 =0 ?

The answer to (x-12)/4+x/2+(x-2x)/9 =0 is x= 108/23

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(x-12)/4+x/2+(x-2x)/9 =0

\frac{x - 12}{4} + \frac{x}{2} + \frac{x - 2 x}{9} = 0

x = \frac{108}{23}

Decimal Notation

x = 4.69565 \dots

Solution steps

\frac{x - 12}{4} + \frac{x}{2} + \frac{x - 2 x}{9} = 0

\frac{x - 2 x}{9} = - \frac{x}{9}

\frac{x - 12}{4} + \frac{x}{2} - \frac{x}{9} = 0

Multiply by LCM

9 (x - 12) + 14 x = 0

Expand

9 (x - 12) + 14 x : 23 x - 108

23 x - 108 = 0

Move

108

to the right side

23 x = 108

Divide both sides by

23

x = \frac{108}{23}

x^{3} - 6 x^{2} - 15 x - 8

4 x^{2} = 8 x

x + 7 = 23

\frac{19 !}{( 19 - 6 ) ! 6 !}

10 > \frac{x}{- 2}

What is the answer to (x-12)/4+x/2+(x-2x)/9 =0 ?
The answer to (x-12)/4+x/2+(x-2x)/9 =0 is x= 108/23
Solve for x: (x-12)/4+x/2+(x-2x)/9 =0
The solution is x= 108/23