What are the solutions to the equation 4x^2-4x+21=0 ?

The solutions to the equation 4x^2-4x+21=0 are x= 1/2+sqrt(5)i,x= 1/2-sqrt(5)i

Find the zeros of 4x^2-4x+21=0

The zeros of 4x^2-4x+21=0 are x= 1/2+sqrt(5)i,x= 1/2-sqrt(5)i

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4 x^{2} - 4 x + 21 = 0

x = \frac{1}{2} + 5 i, x = \frac{1}{2} - 5 i

Solution steps

4 x^{2} - 4 x + 21 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 4 \cdot 21}{2 \cdot 4}

Simplify

(- 4)^{2} - 4 \cdot 4 \cdot 21 : 85 i

x_{1, 2} = \frac{- ( - 4 ) \pm 8 5 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 8 5 i}{2 \cdot 4}, x_{2} = \frac{- ( - 4 ) - 8 5 i}{2 \cdot 4}

x = \frac{- ( - 4 ) + 8 5 i}{2 \cdot 4} : \frac{1}{2} + 5 i

x = \frac{- ( - 4 ) - 8 5 i}{2 \cdot 4} : \frac{1}{2} - 5 i

The solutions to the quadratic equation are:

x = \frac{1}{2} + 5 i, x = \frac{1}{2} - 5 i

\frac{11}{6} - \frac{9}{2}

3 x^{2} + 20 x - 32

\frac{25}{100} \cdot 50

3 (x + 2) < 5 (x + 3)

(- 1)^{4}

What are the solutions to the equation 4x^2-4x+21=0 ?
The solutions to the equation 4x^2-4x+21=0 are x= 1/2+sqrt(5)i,x= 1/2-sqrt(5)i
Find the zeros of 4x^2-4x+21=0
The zeros of 4x^2-4x+21=0 are x= 1/2+sqrt(5)i,x= 1/2-sqrt(5)i