What are the solutions to the equation (x+7)^2= 49/16 ?

The solutions to the equation (x+7)^2= 49/16 are x=-21/4 ,x=-35/4

Find the zeros of (x+7)^2= 49/16

The zeros of (x+7)^2= 49/16 are x=-21/4 ,x=-35/4

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(x + 7)^{2} = \frac{49}{16}

x = - \frac{21}{4}, x = - \frac{35}{4}

Decimal Notation

x = - 5.25, x = - 8.75

Solution steps

(x + 7)^{2} = \frac{49}{16}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 7 = \frac{49}{16} : x = - \frac{21}{4}

Solve

x + 7 = - \frac{49}{16} : x = - \frac{35}{4}

The solutions to the quadratic equation are:

x = - \frac{21}{4}, x = - \frac{35}{4}

\frac{4 + 6 i}{3 i}

x < 3 (x^{2} - 2 x + 1)

5 - 53 i

x^{2} + 4 x - 41 = 0

\frac{36 - x ^{2}}{x + 6} \geq 0

What are the solutions to the equation (x+7)^2= 49/16 ?
The solutions to the equation (x+7)^2= 49/16 are x=-21/4 ,x=-35/4
Find the zeros of (x+7)^2= 49/16
The zeros of (x+7)^2= 49/16 are x=-21/4 ,x=-35/4