What are the solutions to the equation 5x^2+7x=0 ?

The solutions to the equation 5x^2+7x=0 are x=0,x=-7/5

Find the zeros of 5x^2+7x=0

The zeros of 5x^2+7x=0 are x=0,x=-7/5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

5 x^{2} + 7 x = 0

x = 0, x = - \frac{7}{5}

Decimal Notation

x = 0, x = - 1.4

Solution steps

5 x^{2} + 7 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 5 \cdot 0}{2 \cdot 5}

7^{2} - 4 \cdot 5 \cdot 0 = 7

x_{1, 2} = \frac{- 7 \pm 7}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 7 + 7}{2 \cdot 5}, x_{2} = \frac{- 7 - 7}{2 \cdot 5}

x = \frac{- 7 + 7}{2 \cdot 5} : 0

x = \frac{- 7 - 7}{2 \cdot 5} : - \frac{7}{5}

The solutions to the quadratic equation are:

x = 0, x = - \frac{7}{5}

5 x^{2} + 41 x - 36

p m^{2} + 5 m^{2} - q n + p n - q m^{2} + 5 n

\frac{5}{9} (- 67 - 32)

2 a x - ab - a^{2} + 2 b x

11 x^{2} + 8 x - 3 = 0

What are the solutions to the equation 5x^2+7x=0 ?
The solutions to the equation 5x^2+7x=0 are x=0,x=-7/5
Find the zeros of 5x^2+7x=0
The zeros of 5x^2+7x=0 are x=0,x=-7/5