What are the solutions to the equation 1^2+sqrt(11^2)=c^2 ?

The solutions to the equation 1^2+sqrt(11^2)=c^2 are c=2sqrt(3),c=-2sqrt(3)

Find the zeros of 1^2+sqrt(11^2)=c^2

The zeros of 1^2+sqrt(11^2)=c^2 are c=2sqrt(3),c=-2sqrt(3)

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1^{2} + 1 1^{2} = c^{2}

c = 23, c = - 23

Decimal Notation

c = 3.46410 \dots, c = - 3.46410 \dots

Solution steps

1^{2} + 1 1^{2} = c^{2}

Switch sides

c^{2} = 1^{2} + 1 1^{2}

Simplify

1^{2} + 1 1^{2} : 12

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

c = 12, c = - 12

12 = 23

- 12 = - 23

c = 23, c = - 23

x^{2} - 4 > - x^{2} + 4

x y + 2 x + 2 y + 4

(x - 2) \frac{2}{3} = 9

x^{2} - x + 6 < 0

\frac{6 !}{( 6 - 6 ) ! 6 !}

What are the solutions to the equation 1^2+sqrt(11^2)=c^2 ?
The solutions to the equation 1^2+sqrt(11^2)=c^2 are c=2sqrt(3),c=-2sqrt(3)
Find the zeros of 1^2+sqrt(11^2)=c^2
The zeros of 1^2+sqrt(11^2)=c^2 are c=2sqrt(3),c=-2sqrt(3)