What are the solutions to the equation 4x^2+12x+58=0 ?

The solutions to the equation 4x^2+12x+58=0 are x=-3/2+i 7/2 ,x=-3/2-i 7/2

Find the zeros of 4x^2+12x+58=0

The zeros of 4x^2+12x+58=0 are x=-3/2+i 7/2 ,x=-3/2-i 7/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 x^{2} + 12 x + 58 = 0

x = - \frac{3}{2} + i \frac{7}{2}, x = - \frac{3}{2} - i \frac{7}{2}

Solution steps

4 x^{2} + 12 x + 58 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 4 \cdot 58}{2 \cdot 4}

Simplify

1 2^{2} - 4 \cdot 4 \cdot 58 : 28 i

x_{1, 2} = \frac{- 12 \pm 28 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 12 + 28 i}{2 \cdot 4}, x_{2} = \frac{- 12 - 28 i}{2 \cdot 4}

x = \frac{- 12 + 28 i}{2 \cdot 4} : - \frac{3}{2} + i \frac{7}{2}

x = \frac{- 12 - 28 i}{2 \cdot 4} : - \frac{3}{2} - i \frac{7}{2}

The solutions to the quadratic equation are:

x = - \frac{3}{2} + i \frac{7}{2}, x = - \frac{3}{2} - i \frac{7}{2}

4 b - 11 = 1 - 2 (3 - b)

(9 i) (- 5 i)

70 \cdot 7

\frac{x}{3} + \frac{x + 2}{4} - \frac{x + 3}{9} = 3

lo g_{3} (216) = x

What are the solutions to the equation 4x^2+12x+58=0 ?
The solutions to the equation 4x^2+12x+58=0 are x=-3/2+i 7/2 ,x=-3/2-i 7/2
Find the zeros of 4x^2+12x+58=0
The zeros of 4x^2+12x+58=0 are x=-3/2+i 7/2 ,x=-3/2-i 7/2