What is the answer to ((x+2))/4-((x-1))/3 =2 ?

The answer to ((x+2))/4-((x-1))/3 =2 is x=-14

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((x+2))/4-((x-1))/3 =2

\frac{( x + 2 )}{4} - \frac{( x - 1 )}{3} = 2

x = - 14

Solution steps

\frac{( x + 2 )}{4} - \frac{( x - 1 )}{3} = 2

\frac{x + 2}{4} - \frac{x - 1}{3} = 2

Multiply by LCM

3 (x + 2) - 4 (x - 1) = 24

Expand

3 (x + 2) - 4 (x - 1) : - x + 10

- x + 10 = 24

Move

10

to the right side

- x = 14

Divide both sides by

- 1

x = - 14

3 + 2 x = 41

(\frac{3}{4} + \frac{1}{3} - \frac{1}{6} + \frac{1}{3})^{- 1}

5 x^{2} + x - 6

π (3)^{2}

- 6 x^{2} + 6 x + 36 = 0

What is the answer to ((x+2))/4-((x-1))/3 =2 ?
The answer to ((x+2))/4-((x-1))/3 =2 is x=-14
Solve for x: ((x+2))/4-((x-1))/3 =2
The solution is x=-14