What are the solutions to the equation 4x^2+32x+60=0 ?

The solutions to the equation 4x^2+32x+60=0 are x=-3,x=-5

Find the zeros of 4x^2+32x+60=0

The zeros of 4x^2+32x+60=0 are x=-3,x=-5

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4 x^{2} + 32 x + 60 = 0

x = - 3, x = - 5

Solution steps

4 x^{2} + 32 x + 60 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 32 \pm 3 2 ^{2} - 4 \cdot 4 \cdot 60}{2 \cdot 4}

3 2^{2} - 4 \cdot 4 \cdot 60 = 8

x_{1, 2} = \frac{- 32 \pm 8}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 32 + 8}{2 \cdot 4}, x_{2} = \frac{- 32 - 8}{2 \cdot 4}

x = \frac{- 32 + 8}{2 \cdot 4} : - 3

x = \frac{- 32 - 8}{2 \cdot 4} : - 5

The solutions to the quadratic equation are:

x = - 3, x = - 5

3 r^{2} - 16 r - 12

x^{2} + 3 x \geq 10

\frac{2 - 2 i}{i} + \frac{3 - 5 i}{2 - i}

x - 1 = 6

\frac{3}{8} + \frac{5}{12}

What are the solutions to the equation 4x^2+32x+60=0 ?
The solutions to the equation 4x^2+32x+60=0 are x=-3,x=-5
Find the zeros of 4x^2+32x+60=0
The zeros of 4x^2+32x+60=0 are x=-3,x=-5