What are the solutions to the equation 8+96t-16t^2=116 ?

The solutions to the equation 8+96t-16t^2=116 are t= 3/2 ,t= 9/2

Find the zeros of 8+96t-16t^2=116

The zeros of 8+96t-16t^2=116 are t= 3/2 ,t= 9/2

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8 + 96 t - 16 t^{2} = 116

t = \frac{3}{2}, t = \frac{9}{2}

Decimal Notation

t = 1.5, t = 4.5

Solution steps

8 + 96 t - 16 t^{2} = 116

Move

116

to the left side

- 16 t^{2} + 96 t - 108 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 96 \pm 9 6 ^{2} - 4 ( - 16 ) ( - 108 )}{2 ( - 16 )}

9 6^{2} - 4 (- 16) (- 108) = 48

t_{1, 2} = \frac{- 96 \pm 48}{2 ( - 16 )}

Separate the solutions

t_{1} = \frac{- 96 + 48}{2 ( - 16 )}, t_{2} = \frac{- 96 - 48}{2 ( - 16 )}

t = \frac{- 96 + 48}{2 ( - 16 )} : \frac{3}{2}

t = \frac{- 96 - 48}{2 ( - 16 )} : \frac{9}{2}

The solutions to the quadratic equation are:

t = \frac{3}{2}, t = \frac{9}{2}

4 m^{2} = 6

∣ x ∣ \geq 8

64 (1000) - 0.02 (1000)^{2}

∣ y ∣ \leq 8

5 x^{2} + 2 x = - 3

What are the solutions to the equation 8+96t-16t^2=116 ?
The solutions to the equation 8+96t-16t^2=116 are t= 3/2 ,t= 9/2
Find the zeros of 8+96t-16t^2=116
The zeros of 8+96t-16t^2=116 are t= 3/2 ,t= 9/2