What are the solutions to the equation (2w-5)w=52 ?

The solutions to the equation (2w-5)w=52 are w= 13/2 ,w=-4

Find the zeros of (2w-5)w=52

The zeros of (2w-5)w=52 are w= 13/2 ,w=-4

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(2 w - 5) w = 52

w = \frac{13}{2}, w = - 4

Decimal Notation

w = 6.5, w = - 4

Solution steps

(2 w - 5) w = 52

Expand

(2 w - 5) w : 2 w^{2} - 5 w

2 w^{2} - 5 w = 52

Move

52

to the left side

2 w^{2} - 5 w - 52 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 2 ( - 52 )}{2 \cdot 2}

(- 5)^{2} - 4 \cdot 2 (- 52) = 21

w_{1, 2} = \frac{- ( - 5 ) \pm 21}{2 \cdot 2}

Separate the solutions

w_{1} = \frac{- ( - 5 ) + 21}{2 \cdot 2}, w_{2} = \frac{- ( - 5 ) - 21}{2 \cdot 2}

w = \frac{- ( - 5 ) + 21}{2 \cdot 2} : \frac{13}{2}

w = \frac{- ( - 5 ) - 21}{2 \cdot 2} : - 4

The solutions to the quadratic equation are:

w = \frac{13}{2}, w = - 4

540 = 12 z

5 n^{2} - 33 n - 14

3 (- 4 x - 3) + 5 x - 5 = 0

- 3 z + 4 > - 8

\frac{( - 3 ( x + h ) ^{2} ) - ( - 3 x ^{2} )}{h}

What are the solutions to the equation (2w-5)w=52 ?
The solutions to the equation (2w-5)w=52 are w= 13/2 ,w=-4
Find the zeros of (2w-5)w=52
The zeros of (2w-5)w=52 are w= 13/2 ,w=-4