What are the solutions to the equation x^2+6x+3=0 ?

The solutions to the equation x^2+6x+3=0 are x=-3+sqrt(6),x=-3-sqrt(6)

Find the zeros of x^2+6x+3=0

The zeros of x^2+6x+3=0 are x=-3+sqrt(6),x=-3-sqrt(6)

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x^{2} + 6 x + 3 = 0

x = - 3 + 6, x = - 3 - 6

Solution steps

x^{2} + 6 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot 3}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot 3 = 26

x_{1, 2} = \frac{- 6 \pm 2 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 2 6}{2 \cdot 1}, x_{2} = \frac{- 6 - 2 6}{2 \cdot 1}

x = \frac{- 6 + 2 6}{2 \cdot 1} : - 3 + 6

x = \frac{- 6 - 2 6}{2 \cdot 1} : - 3 - 6

The solutions to the quadratic equation are:

x = - 3 + 6, x = - 3 - 6

x^{3} - 6 x^{2} + 8 x

0 = x^{2} + x - 6

x^{2} = 10 x + 10

x^{\frac{3}{2}} + x^{\frac{1}{2}} - 6 x^{- \frac{1}{2}}

- 2 ∣ 3 - 2 x ∣ = - 6

What are the solutions to the equation x^2+6x+3=0 ?
The solutions to the equation x^2+6x+3=0 are x=-3+sqrt(6),x=-3-sqrt(6)
Find the zeros of x^2+6x+3=0
The zeros of x^2+6x+3=0 are x=-3+sqrt(6),x=-3-sqrt(6)