What are the solutions to the equation 4x^2+9=17 ?

The solutions to the equation 4x^2+9=17 are x=sqrt(2),x=-sqrt(2)

Find the zeros of 4x^2+9=17

The zeros of 4x^2+9=17 are x=sqrt(2),x=-sqrt(2)

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4 x^{2} + 9 = 17

x = 2, x = - 2

Solution steps

4 x^{2} + 9 = 17

Move

9

to the right side

4 x^{2} = 8

Divide both sides by

4

x^{2} = 2

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 2, x = - 2

(a^{3})^{2}

- \frac{7 π}{3} - 2 π

92000 \cdot 0.075 \cdot \frac{1}{12}

3 x^{2} - 4 x + 9 x y - 12 y

x^{2} + 15 x = - 56

What are the solutions to the equation 4x^2+9=17 ?
The solutions to the equation 4x^2+9=17 are x=sqrt(2),x=-sqrt(2)
Find the zeros of 4x^2+9=17
The zeros of 4x^2+9=17 are x=sqrt(2),x=-sqrt(2)