What are the solutions to the equation 2^2+4^2=c^2 ?

The solutions to the equation 2^2+4^2=c^2 are c=2sqrt(5),c=-2sqrt(5)

Find the zeros of 2^2+4^2=c^2

The zeros of 2^2+4^2=c^2 are c=2sqrt(5),c=-2sqrt(5)

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2^{2} + 4^{2} = c^{2}

c = 25, c = - 25

Solution steps

2^{2} + 4^{2} = c^{2}

Switch sides

c^{2} = 2^{2} + 4^{2}

Simplify

2^{2} + 4^{2} : 20

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

c = 20, c = - 20

20 = 25

- 20 = - 25

c = 25, c = - 25

- 1 > z + 5

10000 \cdot \frac{1}{( 1 + 0.05 ) ^{3}}

3 x^{2} - 11 x + 6 \leq 0

(\frac{1}{4})^{3}

\frac{y ^{10}}{y ^{- 5}}

What are the solutions to the equation 2^2+4^2=c^2 ?
The solutions to the equation 2^2+4^2=c^2 are c=2sqrt(5),c=-2sqrt(5)
Find the zeros of 2^2+4^2=c^2
The zeros of 2^2+4^2=c^2 are c=2sqrt(5),c=-2sqrt(5)