What are the solutions to the equation z^2+12z+21=0 ?

The solutions to the equation z^2+12z+21=0 are z=-6+sqrt(15),z=-6-sqrt(15)

Find the zeros of z^2+12z+21=0

The zeros of z^2+12z+21=0 are z=-6+sqrt(15),z=-6-sqrt(15)

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z^{2} + 12 z + 21 = 0

z = - 6 + 15, z = - 6 - 15

Solution steps

z^{2} + 12 z + 21 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 1 \cdot 21}{2 \cdot 1}

1 2^{2} - 4 \cdot 1 \cdot 21 = 215

z_{1, 2} = \frac{- 12 \pm 2 15}{2 \cdot 1}

Separate the solutions

z_{1} = \frac{- 12 + 2 15}{2 \cdot 1}, z_{2} = \frac{- 12 - 2 15}{2 \cdot 1}

z = \frac{- 12 + 2 15}{2 \cdot 1} : - 6 + 15

z = \frac{- 12 - 2 15}{2 \cdot 1} : - 6 - 15

The solutions to the quadratic equation are:

z = - 6 + 15, z = - 6 - 15

x (x + 1) < 2

lo g_{8} (60) - lo g_{8} (3) - lo g_{8} (5)

10 q - 15 = 5 (2 q + 4)

3364 g^{2} - 10556 g + 8281

x^{2} + 3 x - 1 < 3

What are the solutions to the equation z^2+12z+21=0 ?
The solutions to the equation z^2+12z+21=0 are z=-6+sqrt(15),z=-6-sqrt(15)
Find the zeros of z^2+12z+21=0
The zeros of z^2+12z+21=0 are z=-6+sqrt(15),z=-6-sqrt(15)