What are the solutions to the equation -2x^2+18=0 ?

The solutions to the equation -2x^2+18=0 are x=3,x=-3

Find the zeros of -2x^2+18=0

The zeros of -2x^2+18=0 are x=3,x=-3

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- 2 x^{2} + 18 = 0

x = 3, x = - 3

Solution steps

- 2 x^{2} + 18 = 0

Move

18

to the right side

- 2 x^{2} = - 18

Divide both sides by

- 2

x^{2} = 9

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 9, x = - 9

9 = 3

- 9 = - 3

x = 3, x = - 3

13 y - 8 y + 15 \leq - 17 + 32

6 x + 3 \geq 9 x - 1

\frac{x - 14}{8} \geq \frac{x - 7}{12} + \frac{1}{24}

\frac{4}{3} z = 10

What are the solutions to the equation -2x^2+18=0 ?
The solutions to the equation -2x^2+18=0 are x=3,x=-3
Find the zeros of -2x^2+18=0
The zeros of -2x^2+18=0 are x=3,x=-3