What are the solutions to the equation 3x^2-8=12 ?

The solutions to the equation 3x^2-8=12 are x=(2sqrt(5))/(sqrt(3)),x=-(2sqrt(5))/(sqrt(3))

Find the zeros of 3x^2-8=12

The zeros of 3x^2-8=12 are x=(2sqrt(5))/(sqrt(3)),x=-(2sqrt(5))/(sqrt(3))

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3 x^{2} - 8 = 12

x = \frac{2 5}{3}, x = - \frac{2 5}{3}

Decimal Notation

x = 2.58198 \dots, x = - 2.58198 \dots

Solution steps

3 x^{2} - 8 = 12

Move

8

to the right side

3 x^{2} = 20

Divide both sides by

3

x^{2} = \frac{20}{3}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{20}{3}, x = - \frac{20}{3}

\frac{20}{3} = \frac{2 5}{3}

- \frac{20}{3} = - \frac{2 5}{3}

x = \frac{2 5}{3}, x = - \frac{2 5}{3}

1 0^{2} + 9^{2} = x^{2}

\frac{13}{4} + \frac{19}{5}

5 x - 15 y

(- 5)^{- 4}

\frac{12 !}{11 !}

What are the solutions to the equation 3x^2-8=12 ?
The solutions to the equation 3x^2-8=12 are x=(2sqrt(5))/(sqrt(3)),x=-(2sqrt(5))/(sqrt(3))
Find the zeros of 3x^2-8=12
The zeros of 3x^2-8=12 are x=(2sqrt(5))/(sqrt(3)),x=-(2sqrt(5))/(sqrt(3))