What are the solutions to the equation 6x^2-3x+4=8x+1 ?

The solutions to the equation 6x^2-3x+4=8x+1 are x= 3/2 ,x= 1/3

Find the zeros of 6x^2-3x+4=8x+1

The zeros of 6x^2-3x+4=8x+1 are x= 3/2 ,x= 1/3

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6 x^{2} - 3 x + 4 = 8 x + 1

x = \frac{3}{2}, x = \frac{1}{3}

Decimal Notation

x = 1.5, x = 0.33333 \dots

Solution steps

6 x^{2} - 3 x + 4 = 8 x + 1

Move

1

to the left side

6 x^{2} - 3 x + 3 = 8 x

Move

8 x

to the left side

6 x^{2} - 11 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 6 \cdot 3}{2 \cdot 6}

(- 11)^{2} - 4 \cdot 6 \cdot 3 = 7

x_{1, 2} = \frac{- ( - 11 ) \pm 7}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 11 ) + 7}{2 \cdot 6}, x_{2} = \frac{- ( - 11 ) - 7}{2 \cdot 6}

x = \frac{- ( - 11 ) + 7}{2 \cdot 6} : \frac{3}{2}

x = \frac{- ( - 11 ) - 7}{2 \cdot 6} : \frac{1}{3}

The solutions to the quadratic equation are:

x = \frac{3}{2}, x = \frac{1}{3}

4 x^{2} - 13 x - 12

2 x^{2} - 2 x + 1 = 0

9 x^{2} + 15 + 6

x^{2} - 6 x + 8 \leq 0

6 (x - 1) = 3 x - 2

What are the solutions to the equation 6x^2-3x+4=8x+1 ?
The solutions to the equation 6x^2-3x+4=8x+1 are x= 3/2 ,x= 1/3
Find the zeros of 6x^2-3x+4=8x+1
The zeros of 6x^2-3x+4=8x+1 are x= 3/2 ,x= 1/3