What are the solutions to the equation 3w^2+22w+7=0 ?

The solutions to the equation 3w^2+22w+7=0 are w=-1/3 ,w=-7

Find the zeros of 3w^2+22w+7=0

The zeros of 3w^2+22w+7=0 are w=-1/3 ,w=-7

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3 w^{2} + 22 w + 7 = 0

w = - \frac{1}{3}, w = - 7

Solution steps

3 w^{2} + 22 w + 7 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- 22 \pm 2 2 ^{2} - 4 \cdot 3 \cdot 7}{2 \cdot 3}

2 2^{2} - 4 \cdot 3 \cdot 7 = 20

w_{1, 2} = \frac{- 22 \pm 20}{2 \cdot 3}

Separate the solutions

w_{1} = \frac{- 22 + 20}{2 \cdot 3}, w_{2} = \frac{- 22 - 20}{2 \cdot 3}

w = \frac{- 22 + 20}{2 \cdot 3} : - \frac{1}{3}

w = \frac{- 22 - 20}{2 \cdot 3} : - 7

The solutions to the quadratic equation are:

w = - \frac{1}{3}, w = - 7

m^{2} - 15 m + 50

\frac{x}{2} - 3 = \frac{3 x}{5} + 1

(x + 2) (x - 6) \leq 0

9 x^{2} - 3 x

\frac{4}{2 - 5 i}

What are the solutions to the equation 3w^2+22w+7=0 ?
The solutions to the equation 3w^2+22w+7=0 are w=-1/3 ,w=-7
Find the zeros of 3w^2+22w+7=0
The zeros of 3w^2+22w+7=0 are w=-1/3 ,w=-7