What is factor 4j^2+8j+3 ?

The solution to factor 4j^2+8j+3 is (2j+1)(2j+3)

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factor 4j^2+8j+3

factor

4 j^{2} + 8 j + 3

(2 j + 1) (2 j + 3)

Solution steps

4 j^{2} + 8 j + 3

Break the expression into groups

= (4 j^{2} + 2 j) + (6 j + 3)

Factor out

2 j

from

4 j^{2} + 2 j : 2 j (2 j + 1)

Factor out

3

from

6 j + 3 : 3 (2 j + 1)

= 2 j (2 j + 1) + 3 (2 j + 1)

Factor out common term

2 j + 1

= (2 j + 1) (2 j + 3)

\frac{4}{3} x + 3 = 19

lo g_{8} (16) = x

\frac{- 1}{6}

2 (5 - x)^{3} - 3 (5 - x)^{2}

\frac{x}{10} + 3 = 10