What are the solutions to the equation z^2-z-30=0 ?

The solutions to the equation z^2-z-30=0 are z=6,z=-5

Find the zeros of z^2-z-30=0

The zeros of z^2-z-30=0 are z=6,z=-5

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z^{2} - z - 30 = 0

z = 6, z = - 5

Solution steps

z^{2} - z - 30 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 30 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 30) = 11

z_{1, 2} = \frac{- ( - 1 ) \pm 11}{2 \cdot 1}

Separate the solutions

z_{1} = \frac{- ( - 1 ) + 11}{2 \cdot 1}, z_{2} = \frac{- ( - 1 ) - 11}{2 \cdot 1}

z = \frac{- ( - 1 ) + 11}{2 \cdot 1} : 6

z = \frac{- ( - 1 ) - 11}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

z = 6, z = - 5

- 4 x + 2 < 2 x - 6

\frac{150}{96}

- (\frac{1}{- 4})

∣ 3 x - 2 ∣ + 6 = x

(9 - t) (3 - t) = (4 - t) (t + 9)

What are the solutions to the equation z^2-z-30=0 ?
The solutions to the equation z^2-z-30=0 are z=6,z=-5
Find the zeros of z^2-z-30=0
The zeros of z^2-z-30=0 are z=6,z=-5