What are the solutions to the equation p^2+4p-21=0 ?

The solutions to the equation p^2+4p-21=0 are p=3,p=-7

Find the zeros of p^2+4p-21=0

The zeros of p^2+4p-21=0 are p=3,p=-7

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p^{2} + 4 p - 21 = 0

p = 3, p = - 7

Solution steps

p^{2} + 4 p - 21 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( - 21 )}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot (- 21) = 10

p_{1, 2} = \frac{- 4 \pm 10}{2 \cdot 1}

Separate the solutions

p_{1} = \frac{- 4 + 10}{2 \cdot 1}, p_{2} = \frac{- 4 - 10}{2 \cdot 1}

p = \frac{- 4 + 10}{2 \cdot 1} : 3

p = \frac{- 4 - 10}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

p = 3, p = - 7

- 3 x + \frac{5 x}{9} = \frac{4}{3} - 2 x

- (- 5)^{3}

4 (9) - 7

(k + 2)^{2} = 28

\frac{x - 1}{x + 1} \leq 2

What are the solutions to the equation p^2+4p-21=0 ?
The solutions to the equation p^2+4p-21=0 are p=3,p=-7
Find the zeros of p^2+4p-21=0
The zeros of p^2+4p-21=0 are p=3,p=-7