What is (4^{-3}a^0)/(b^{-7)} ?

The solution to (4^{-3}a^0)/(b^{-7)} is (b^7)/(64)

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simplify (4^{-3}a^0)/(b^{-7)}

simplify

\frac{4 ^{- 3} a ^{0}}{b ^{- 7}}

\frac{b ^{7}}{64}

Solution steps

\frac{4 ^{- 3} a ^{0}}{b ^{- 7}}

Simplify

4^{- 3} a^{0} : \frac{1}{64}

= \frac{\frac{1}{64}}{b ^{- 7}}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{1}{64 b ^{- 7}}

Simplify

64 b^{- 7} : \frac{64}{b ^{7}}

= \frac{1}{\frac{64}{b ^{7}}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{b ^{7}}{64}

(- 5)^{2}

x^{3} - 7 x^{2} + 5 = x (x^{2} - 1) + 3 x^{2} - 2

3 + 2 x \leq 7

e = (10 x 1.5) - (10 x 1.5) x 0.06

7 n^{2} + 10 n + 3

What is (4^{-3}a^0)/(b^{-7)} ?
The solution to (4^{-3}a^0)/(b^{-7)} is (b^7)/(64)