What are the solutions to the equation x^2-8x-15=0 ?

The solutions to the equation x^2-8x-15=0 are x=4+sqrt(31),x=4-sqrt(31)

Find the zeros of x^2-8x-15=0

The zeros of x^2-8x-15=0 are x=4+sqrt(31),x=4-sqrt(31)

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x^{2} - 8 x - 15 = 0

x = 4 + 31, x = 4 - 31

Solution steps

x^{2} - 8 x - 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot ( - 15 )}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot (- 15) = 231

x_{1, 2} = \frac{- ( - 8 ) \pm 2 31}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 2 31}{2 \cdot 1}, x_{2} = \frac{- ( - 8 ) - 2 31}{2 \cdot 1}

x = \frac{- ( - 8 ) + 2 31}{2 \cdot 1} : 4 + 31

x = \frac{- ( - 8 ) - 2 31}{2 \cdot 1} : 4 - 31

The solutions to the quadratic equation are:

x = 4 + 31, x = 4 - 31

\frac{2 x - 4}{5} + 6 = 8

- 5.3 \geq 3.6 x

\frac{( 2 + 0.01 ) ^{3} - 8}{0.01}

- \frac{1}{3} (6) - \frac{3 - 4 ( 6 )}{2}

\frac{x}{25} > 5

What are the solutions to the equation x^2-8x-15=0 ?
The solutions to the equation x^2-8x-15=0 are x=4+sqrt(31),x=4-sqrt(31)
Find the zeros of x^2-8x-15=0
The zeros of x^2-8x-15=0 are x=4+sqrt(31),x=4-sqrt(31)