What are the solutions to the equation (x+4)^2=-9 ?

The solutions to the equation (x+4)^2=-9 are x=3i-4,x=-3i-4

Find the zeros of (x+4)^2=-9

The zeros of (x+4)^2=-9 are x=3i-4,x=-3i-4

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(x + 4)^{2} = - 9

x = 3 i - 4, x = - 3 i - 4

Solution steps

(x + 4)^{2} = - 9

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 4 = - 9 : x = 3 i - 4

Solve

x + 4 = - - 9 : x = - 3 i - 4

The solutions to the quadratic equation are:

x = 3 i - 4, x = - 3 i - 4

1 + 2 x < 9

x^{2} - 4 x - 60 = 0

16 j^{2} k - 8 j^{6} k^{5} + 60 j^{3}

15 x - 12 (0) = 16

\frac{3 y ^{\frac{1}{4}}}{4 x ^{- \frac{2}{3}} y ^{\frac{3}{2}} \cdot 3 y ^{\frac{1}{2}}}

What are the solutions to the equation (x+4)^2=-9 ?
The solutions to the equation (x+4)^2=-9 are x=3i-4,x=-3i-4
Find the zeros of (x+4)^2=-9
The zeros of (x+4)^2=-9 are x=3i-4,x=-3i-4