What is -2+sqrt(8-4z)>= 8 ?

The solution to -2+sqrt(8-4z)>= 8 is z<=-23

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-2+sqrt(8-4z)>= 8

- 2 + 8 - 4 z \geq 8

z \leq - 23

Interval Notation

(- \infty, - 23]

Solution steps

- 2 + 8 - 4 z \geq 8

Move

2

to the right side

8 - 4 z \geq 10

Square both sides

(8 - 4 z)^{2} \geq 1 0^{2}

Simplify

8 - 4 z \geq 100

8 - 4 z \geq 100 : z \leq - 23

z \leq - 23

Find singularity points

Find non-negative values for radicals:

z \leq 2

Combine the intervals

z \leq - 23 and z \leq 2

Merge Overlapping Intervals

z \leq - 23

\frac{x ^{2} + 2 x}{x ^{2} - 4} \geq 0

4 t - 3 = - 21

- 212 = - 4 (6 n + 5)

- 2 < 2 x + 1 < 5

\frac{3 a ^{2}}{9 a ^{2}}