What are the solutions to the equation 66-x^2+x=10 ?

The solutions to the equation 66-x^2+x=10 are x=-7,x=8

Find the zeros of 66-x^2+x=10

The zeros of 66-x^2+x=10 are x=-7,x=8

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66 - x^{2} + x = 10

x = - 7, x = 8

Solution steps

66 - x^{2} + x = 10

Move

10

to the left side

- x^{2} + x + 56 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 ( - 1 ) \cdot 56}{2 ( - 1 )}

1^{2} - 4 (- 1) \cdot 56 = 15

x_{1, 2} = \frac{- 1 \pm 15}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 1 + 15}{2 ( - 1 )}, x_{2} = \frac{- 1 - 15}{2 ( - 1 )}

x = \frac{- 1 + 15}{2 ( - 1 )} : - 7

x = \frac{- 1 - 15}{2 ( - 1 )} : 8

The solutions to the quadratic equation are:

x = - 7, x = 8

x^{2} + 3 x \geq - 2

x + 4 = 9

- 5 y - 7 \leq 3

12 < - 3 (x - 2) < 24

(4) + \frac{2 ( - 5 ) ( - 7 )}{3 ( 4 )}

What are the solutions to the equation 66-x^2+x=10 ?
The solutions to the equation 66-x^2+x=10 are x=-7,x=8
Find the zeros of 66-x^2+x=10
The zeros of 66-x^2+x=10 are x=-7,x=8