What are the solutions to the equation 4x^2+7+5x+8=3x^2-3x ?

The solutions to the equation 4x^2+7+5x+8=3x^2-3x are x=-3,x=-5

Find the zeros of 4x^2+7+5x+8=3x^2-3x

The zeros of 4x^2+7+5x+8=3x^2-3x are x=-3,x=-5

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4 x^{2} + 7 + 5 x + 8 = 3 x^{2} - 3 x

x = - 3, x = - 5

Solution steps

4 x^{2} + 7 + 5 x + 8 = 3 x^{2} - 3 x

Refine

4 x^{2} + 5 x + 15 = 3 x^{2} - 3 x

Move

3 x

to the left side

4 x^{2} + 8 x + 15 = 3 x^{2}

Move

3 x^{2}

to the left side

x^{2} + 8 x + 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 15}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot 15 = 2

x_{1, 2} = \frac{- 8 \pm 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 2}{2 \cdot 1}, x_{2} = \frac{- 8 - 2}{2 \cdot 1}

x = \frac{- 8 + 2}{2 \cdot 1} : - 3

x = \frac{- 8 - 2}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

x = - 3, x = - 5

0.25 a + 0.5 = 4.5

3 d - 4 = 8

\frac{7}{3} + \frac{10}{3} y = 3 y - 4

- m^{2} \cdot 4 r^{3} \cdot 12 r^{- 4} \cdot 5 m

\frac{( 25 x ^{4} + 30 x ^{2} y + 9 y ^{2} )}{5 x ^{2} + 3 y}

What are the solutions to the equation 4x^2+7+5x+8=3x^2-3x ?
The solutions to the equation 4x^2+7+5x+8=3x^2-3x are x=-3,x=-5
Find the zeros of 4x^2+7+5x+8=3x^2-3x
The zeros of 4x^2+7+5x+8=3x^2-3x are x=-3,x=-5