What are the solutions to the equation x^2-17x+16=0 ?

The solutions to the equation x^2-17x+16=0 are x=16,x=1

Find the zeros of x^2-17x+16=0

The zeros of x^2-17x+16=0 are x=16,x=1

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x^{2} - 17 x + 16 = 0

x = 16, x = 1

Solution steps

x^{2} - 17 x + 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 17 ) \pm ( - 17 ) ^{2} - 4 \cdot 1 \cdot 16}{2 \cdot 1}

(- 17)^{2} - 4 \cdot 1 \cdot 16 = 15

x_{1, 2} = \frac{- ( - 17 ) \pm 15}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 17 ) + 15}{2 \cdot 1}, x_{2} = \frac{- ( - 17 ) - 15}{2 \cdot 1}

x = \frac{- ( - 17 ) + 15}{2 \cdot 1} : 16

x = \frac{- ( - 17 ) - 15}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

x = 16, x = 1

1 \leq y \leq 3

2 y^{3} + 5 y^{2} - 6 y - 15

\frac{- 3}{4} m + \frac{1}{2} m - \frac{1}{2} m = \frac{- 7}{12}

4 x y + 10 x^{2} y^{3} - 6 x^{4}

4.4 ∣ 0.5 - x ∣ + 2 = 4.2

What are the solutions to the equation x^2-17x+16=0 ?
The solutions to the equation x^2-17x+16=0 are x=16,x=1
Find the zeros of x^2-17x+16=0
The zeros of x^2-17x+16=0 are x=16,x=1