What are the solutions to the equation -x^2+x-1=0 ?

The solutions to the equation -x^2+x-1=0 are x= 1/2-i(sqrt(3))/2 ,x= 1/2+i(sqrt(3))/2

Find the zeros of -x^2+x-1=0

The zeros of -x^2+x-1=0 are x= 1/2-i(sqrt(3))/2 ,x= 1/2+i(sqrt(3))/2

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- x^{2} + x - 1 = 0

x = \frac{1}{2} - i \frac{3}{2}, x = \frac{1}{2} + i \frac{3}{2}

Solution steps

- x^{2} + x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 ( - 1 ) ( - 1 )}{2 ( - 1 )}

Simplify

1^{2} - 4 (- 1) (- 1) : 3 i

x_{1, 2} = \frac{- 1 \pm 3 i}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 1 + 3 i}{2 ( - 1 )}, x_{2} = \frac{- 1 - 3 i}{2 ( - 1 )}

x = \frac{- 1 + 3 i}{2 ( - 1 )} : \frac{1}{2} - i \frac{3}{2}

x = \frac{- 1 - 3 i}{2 ( - 1 )} : \frac{1}{2} + i \frac{3}{2}

The solutions to the quadratic equation are:

x = \frac{1}{2} - i \frac{3}{2}, x = \frac{1}{2} + i \frac{3}{2}

∣ 2 x + 7 ∣ < 3

(a^{5})^{2}

0.157 = 0.0003 x - 1^{- 5}

4 (x + 2) + x + 1 = 2 x - 3 + 3 (x + 4)

(3 + 2 + \frac{1}{3 + 2})^{2}

What are the solutions to the equation -x^2+x-1=0 ?
The solutions to the equation -x^2+x-1=0 are x= 1/2-i(sqrt(3))/2 ,x= 1/2+i(sqrt(3))/2
Find the zeros of -x^2+x-1=0
The zeros of -x^2+x-1=0 are x= 1/2-i(sqrt(3))/2 ,x= 1/2+i(sqrt(3))/2