What are the solutions to the equation 8x^2+7x-2=0 ?

The solutions to the equation 8x^2+7x-2=0 are x=(-7+sqrt(113))/(16),x=(-7-sqrt(113))/(16)

Find the zeros of 8x^2+7x-2=0

The zeros of 8x^2+7x-2=0 are x=(-7+sqrt(113))/(16),x=(-7-sqrt(113))/(16)

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8 x^{2} + 7 x - 2 = 0

x = \frac{- 7 + 113}{16}, x = \frac{- 7 - 113}{16}

Solution steps

8 x^{2} + 7 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 8 ( - 2 )}{2 \cdot 8}

7^{2} - 4 \cdot 8 (- 2) = 113

x_{1, 2} = \frac{- 7 \pm 113}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- 7 + 113}{2 \cdot 8}, x_{2} = \frac{- 7 - 113}{2 \cdot 8}

x = \frac{- 7 + 113}{2 \cdot 8} : \frac{- 7 + 113}{16}

x = \frac{- 7 - 113}{2 \cdot 8} : \frac{- 7 - 113}{16}

The solutions to the quadratic equation are:

x = \frac{- 7 + 113}{16}, x = \frac{- 7 - 113}{16}

(3 + 10) (3 - 210)

8 x^{2} - 8 x - 15 = 5 x^{2}

9 = 18 - 0.3 x

10 \cdot 9 \cdot 8 \cdot 7 \cdot 6

24 = - 11 v - 8 + 3 v

What are the solutions to the equation 8x^2+7x-2=0 ?
The solutions to the equation 8x^2+7x-2=0 are x=(-7+sqrt(113))/(16),x=(-7-sqrt(113))/(16)
Find the zeros of 8x^2+7x-2=0
The zeros of 8x^2+7x-2=0 are x=(-7+sqrt(113))/(16),x=(-7-sqrt(113))/(16)