What are the solutions to the equation y^2-2y+10=0 ?

The solutions to the equation y^2-2y+10=0 are y=1+3i,y=1-3i

Find the zeros of y^2-2y+10=0

The zeros of y^2-2y+10=0 are y=1+3i,y=1-3i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{2} - 2 y + 10 = 0

y = 1 + 3 i, y = 1 - 3 i

Solution steps

y^{2} - 2 y + 10 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot 10}{2 \cdot 1}

Simplify

(- 2)^{2} - 4 \cdot 1 \cdot 10 : 6 i

y_{1, 2} = \frac{- ( - 2 ) \pm 6 i}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 2 ) + 6 i}{2 \cdot 1}, y_{2} = \frac{- ( - 2 ) - 6 i}{2 \cdot 1}

y = \frac{- ( - 2 ) + 6 i}{2 \cdot 1} : 1 + 3 i

y = \frac{- ( - 2 ) - 6 i}{2 \cdot 1} : 1 - 3 i

The solutions to the quadratic equation are:

y = 1 + 3 i, y = 1 - 3 i

2^{(\frac{1}{2})}

u^{2} + 8 u + 16

x^{3} + 4 x^{2} + 8 x + 32

8 x - 27 = 7 x - 4

4 x (9 - 3 x) = 8 x - 1

What are the solutions to the equation y^2-2y+10=0 ?
The solutions to the equation y^2-2y+10=0 are y=1+3i,y=1-3i
Find the zeros of y^2-2y+10=0
The zeros of y^2-2y+10=0 are y=1+3i,y=1-3i